Question

mahesh sold two cell phones at rupees 9900 each . On one he 10% and on the other he lost 10% .Find ?
the cost price of each cell phone.
the total profit or loss in the whole transaction .
his total profit or loss %
​

Answer 1

Answer:

1st cellphone =9900

SP =9900

GAIN=10%

CP=100/100+G×SP

=100/100+10×9900

=100/110×9900

9000

2ND CELLPHONE

SP =9900

LOSS=10%

CP=100/100-10×9900

=100/90×9900

100×110=11000

total CP of two cell phones=9000+11000=20000

SP of two cell phones=9900+9900

=19800

since CP is greater than SP

loss= 2000-19800 =200

LOSS %=200/20000 ×100=1%LOSS

PLEASE MARK AS THE BRAINLIEST

Answer 2

Answer:

Step-by-step explanation:

Solution:

Selling price of 1

st cell phone = Rs. 9900

Selling price of 2nd cell phone = Rs. 9900

On one cell phone he gained 10% and on other he gained 10% loss

Let the CP of 1st mobile phone be x

Hence,

Selling price of 1st cell phone = (100+Profit %)/100 x C. P.

9900 = (110/100) X x

9900 = 11x/10

x = (9900x10) x 11 = Rs. 9000

C. P. of 1st cell phone = Rs. 9000

Let the CP of 1st mobile phone be X

Selling price of 2nd cell phone = (100-Loss %)/100 x C. P.

9900 = (90/100) x X

9900 = 9X/10

X = (9900x10) / 9 = Rs. 11000

C. P. of 2nd cell phone = Rs. 11,000

Selling price of 1st cell phone + Selling price of 2nd cell phone = 9900 + 9900 = Rs. 19800

Cost price of 1

st cell phone + Cost price of 2nd cell phone = 9000+11000 = Rs. 20000

Here, total CP > total SP, Hence, it is a loss

Loss = CP – SP = 20000-19800 = Rs. 200

% Loss =

Loss

C.P.

x 100

=

200

20000

x 100

= 1%

Mahesh % loss = 1%