Mahindra and Virat are sitting at a distance of 1 m from each other their masses 45 kg and 50 kg respectively what is the gravitational force between them
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Given,
mass of the first person m1=45kg
Masson the second person m2=50kg
distance between them r=1m=100cm
gravitational force g=Gm1m2/r
g=9.8×45×50/1
g=22050
mass of the first person m1=45kg
Masson the second person m2=50kg
distance between them r=1m=100cm
gravitational force g=Gm1m2/r
g=9.8×45×50/1
g=22050
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