Mahindra and Virat are sitting at a distance of 1 m from each other their masses 45 kg and 50 kg respectively what is the gravitational force between them
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Gravitational force = GMm/r²
G = 6.673×10-11 N m2 kg-2
M = 45kg
m = 50 kg
r = 1m
So, Gravitational force =(6.67 x 10-11x45x50)/1²
= 15.007 x 10^(-14) N
G = 6.673×10-11 N m2 kg-2
M = 45kg
m = 50 kg
r = 1m
So, Gravitational force =(6.67 x 10-11x45x50)/1²
= 15.007 x 10^(-14) N
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