Maitri and Aabhas do a work in 12 hours. Aabhas and kavya do work in 15 hours. Kavya and Maitri do the work in 20 hours. In how many hours will they finish it together and separately?
Answers
Step-by-step explanation:
Work done by Maitri and Abhas in 1 hour = 1/12
Work done by Abhas and Kavya in 1 hour = 1/15
Work done by Kavya and Maitri in 1 hour = 1/20
Add the numbers
Maitri and Abhas + Abhas and Kavya + Kavya and Maitri=
1/12 + 1/15 + 1/20
=1/5
2(Maitri + Abhas + Kavya) = 1/5
Maitri + Abhas + Kavya = 1/5 × 1/2 = 1/10th of work in 1 day
Therefore, Maitri, Abhas and Kavya do the work together in 10 days.
Now add
Maitri and Abhas + Maitri and Kavya= 1/12 + 1/20 = 8/60
2(Maitri) + Kavya and Abhas
It is given that Kavya and Abhas do the work together in 15 hours.
So Subtract it from 8/60
8/60-1/15 = 4/60 = 1/15
1/15 × 1/2 = 1/30.
Maitri do the work in 30 hours
Do the same process for others.
Please mark the answer as brainliest.
Work done by Maitri and Abhas in 1 hour = 1/12
Work done by Abhas and Kavya in 1 hour = 1/15
Work done by Kavya and Maitri in 1 hour = 1/20
Add the numbers
Maitri and Abhas + Abhas and Kavya + Kavya and Maitri=
1/12 + 1/15 + 1/20
=1/5
2(Maitri + Abhas + Kavya) = 1/5
Maitri + Abhas + Kavya = 1/5 × 1/2 = 1/10th of work in 1 day
Therefore, Maitri, Abhas and Kavya do the work together in 10 days.
Now add
Maitri and Abhas + Maitri and Kavya= 1/12 + 1/20 = 8/60
2(Maitri) + Kavya and Abhas
It is given that Kavya and Abhas do the work together in 15 hours.
So Subtract it from 8/60
8/60-1/15 = 4/60 = 1/15
1/15 × 1/2 = 1/30.
Maitri do the work in 30 hours
Do the same process for others.