Question

make a linear equation: in a basketball game, mohan scored 4 more than twice as many as rohan. If one of them had scored 2 more points, their total would be 60.How many point did each score?​

Answer 1

${\mathcal{\red{ANSWER}}}$

Let Rohan's score = x

And, Mohan's score = y

According to question,

$\tt{y=2x+4\;\;\;\;.......(1)}$

And,

Let Rohan score 2 more points. So,

$\tt{\implies x+2+y=60}$

$\tt{\implies x+y=58\;\;\;\;.......(2)}$

Subtracting equation (1) and (2),

$\tt{\implies -x=2x-54}$

$\tt{\implies 3x=54}$

$\tt{\implies x=18}$

${\boxed{\boxed{\tt{Rohan's\;score=18}}}}$

And,

${\boxed{\boxed{\tt{Mohan's\;score=18\times 2 + 4=40}}}}$

Answer 2

Rohan scored 18 points and Mohan scored 40 points in the game.

Given:

In a basketball game, Mohan scored 4 more than twice as many as Rohan. If one of them had scored 2 more points, their total would be 60.

To find:

How many points did each score?​

Solution:

Let's assume that Rohan's score in the game is "x".

Given that Mohan scored 4 more than twice as many as Rohan.

=> Points scored by Mohan = 2x + 4.

Let Rohan score 2 more points

The total points scored by Rohan = x + 2

Here their total would be 60.

=> (x + 2) + (2x + 4) = 60

=> 3x + 6 = 60

=> 3x = 54

=> x = 18

Thus,

Rohan's score in the game is 18 points.

Mohan's score can be calculated as

2x + 4 = 2(18) + 4 = 40.

Therefore,

Rohan scored 18 points and Mohan scored 40 points in the game.

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https://brainly.in/question/32894586

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