Question

Man a of mass 60 kg pushes the other man b of mass 75kg due to which man b starts moving with acceleration 3m/s2 calculate the acceleration of man a, at that instant

Answer 1

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Mass of Man A (m1) = 60kg

Mass of Man B (m2) = 75 kg

Acceleration of Man B (a2) = 3m/${s}^{2}$

Accelration of Man A (a1) = ?


Here we can use the linear momentum formula that is


=》 m1 a1 = m2 a2

=》 60×a1 = 75× 3

=》 a1 = $\frac{225}{60}$


=》 a1 = 3.75 m/${s}^{2}$ Ans



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Hope this helps . . . . . .