Question

man buys a thing first its price increases 10percent then its price decrease 10 percent what is the lose or profit percentage​

Answer 1

Answer:

$let \: cp \: = 100 \\ p\% = 10\% \\ sp = \frac{cp(100 + p\%)}{100 } \\ = \frac{100(100 + 10)}{100} \\ = 110 \\ \\ now \: cp = 110 \\ loss\% = 10\% \\ sp = \frac{cp (100- l\%)}{100} \\ = \frac{110(100 - 10)}{100} \\ = 11 \times \frac{90}{10} \\ = 99 \\ \\ loss\% = \frac{cp - sp}{cp} \times 100 \\ = \frac{100 - 99}{100} \times 100 \\ = 1\%$