Question

Man sold 50 kg more than 1/3 of his total quantity of rice .again he sold 50 kg more than 1/2 of the remaining quantity.If the total remaining quantity is 250 kg then how much stock did he originally have?​

Answer 1

Answer:

Let the original stock f rice be x kg Parts of the stock sold first time =(

3

2x

+100)kg

∴ Remaining stock = [x−(

3

2x

+100)]kg=(

3

x

−100)kg

Part of the stock sold second time

=[

2

1

(

3

x

−100)+100]=(

6

x

−50+100)kg=(

6

x

+50)kg

∴ Remaining stock =(

3

x

−100)−(

6

x

+50)=(

3

x

−

6

x

−100−50)kg=(

6

x

−150)kg

Given

6

x

−150=150⇒

6

x

=300⇒x=1800kg