Question

man throws a ball 25m/s up find max. hieght range and time​

Answer 1

Answer:

u=25

v=0

t=?

h=?

g=-10

v^2=u^2 +2gh

0=25^2+2*-10*h

0=625-20h

20h=625

h=625/20

h=31.25

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