Question

Manish lent 15000 to Rahul for 3 years 10% p.a find the compound interest paid by Rahul​

Answer 1

Answer:

4465

Step-by-step explanation:

compound interest = p(1+r/100)^n-p

p(1+10/100)^3-p

p=15000( principal )

15000(11/10)^3-15000

15000(1331/1000)-15000

19965-1500

4665= compound interest

Answer 2

Answer:

$amount = p \times(1 + \frac{ {r}^{} }{100} { )}^{t} \\ = 15000 \times (1 + \frac{10}{100} ) {}^{3} \\ = 15000 \times (\frac{110}{100} ) {}^{3} \\ = 15000 \times \frac{110}{100} \times \frac{110}{100} \times \frac{110}{100} \\ = 15 \times 11 \times 11 \times 11 \\ = 19965$

C.I=Amount-principal

=19965-15000

=4965 rupees

Step-by-step explanation:

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