Question

Manju had a chocolate .she gave one-fourth of it to raji,one-third to sugatha and one-sixth to sheela.she ate the remaining part. how many pieces of chocolate did each get​

Answer 1

Answer:

total number of pieces are 12

given : manju had a chocolate. She gave one-fourth of it to raji, one Third to sugatha and one-sixth to sheela. she ate the remaining part

to find :how many pieces of chocolate did each get?

solutions :

let the complete chocolate manju has be '1'

she gave one-fourth of it to raji I. e. \frac {1}{4}

4

1

she gave one third to sugatha I. e. \frac{1}{3}

3

1

she gave one-sixth to sheela I. e. \frac{1}{6}

6

1

first we take a common denominator of all three fraction I. e. 12.

so, raji would have \frac.{3}{12}

12

3

of other chocolate bar

sugatha would have \frac{4}{12

4

of the chocolate bar.

sheela would have \frac,{2}{12}

12

2

of the chocolate bar

manju ate the remaining

R=\frac{12-3-4-2)}{12}=\frac{3}{12}=\frac{3}{12}=\frac. {1}{4}r=(12-3-4-2)

=

12

3

=

4

1