Math, asked by parimaraval2005, 1 year ago

manju Kutty has a total of Rs.760 as currency notes In the denominations of Rs.50, Rs.20 and Rs.10.the ratio of the number of Rs.50 notes to Rs.20 notes is 3:5. if she has a total of 25 notes, find the number of notes of each denomination she has.

Answers

Answered by keshav65
5
50×9=450
20×15=300
10×1=10
450+300+10=760
Answered by kbdevi77
12

Answer:

No of 50 Rupee coin is = 9

No. of 20 Rupee Coin is = 15

No. of 10 Rupee coin is = 1



Step-by-step explanation:

Let the no. of Rs.10 coin be "X"

Total no.of coins = 25

Now  no. of Rs.50 coin and Rs. 20 coin will be = 25 - X

Ratio Given for 50 & 20 Rupee coin is 3:5

Total no. of Rs.50 coin = (25-X)*3/8 ( as per ratio given)

Sum of Rs.50 = 50*3/5(25-X)

Total No. of Rs.20 coin = (25-X)*5/8

Sum of Rs.20 = 20*5/8(25-X)

Given that : Sum of 25 coins denominations is 760

so,       50*3/8(25-X) + 20*5/8(25-X) + 10X = 760

  we are going to take common term

          (25-X)(50*3/8 + 20*5/8)+10X = 760

           (25-X)(150/8 +100/8)+10X = 760

           (25-X)(250/8)+10X = 760

           (25-X) (125/4)+10X = 760

Now multiplying (25-X) and 125/4

        (3125-125X)/4+ 10X = 760

        ( 3125-125X + 4*10X)/4 = 760

          3125-125X + 40X = 760 * 4

           3125 - 85X = 3040

           3125-3040 = 85X

            85 = 85X

              X = 85/85

                X = 1

IF X = 1

that is no. of 10 Rupee coin is "1"

No. of 50 Rupee coin is = (25-X)*3/8

                                        = (25-1)*3/8

                                         =24*3/8

                                          =3*3

                                          = 9

No. of 20 Rupee coin is = (25-X) * 5/8

                                         = (25-1)*5/8

                                          = 24*5/8

                                           = 3*5

                                           =15

Hence proved that

       Rs.50*9 + Rs.20*15 + Rs.10*1

             450+300+10

             760

   



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