manjula thinks a number and subtracts7/3 from it .she multiplies the result by 6 the result obtained is 2 less than twice number the same number she thought of.what is the number
Answers
Answered by
50
Here is your answer.
Let the number she thought be x.
Now, As per the question,
(x-7/3) * 6 = 2x - 2
=> (x-7/3) = 6(2x-2)
=> (3x-7)/3 = 12x-12
=> 3x-7 = 36x -36
=> 3x-36x = 7-36
=> 33x = 29
=> x = 29/33.
Thus, Required answer will be 29/33.
Let the number she thought be x.
Now, As per the question,
(x-7/3) * 6 = 2x - 2
=> (x-7/3) = 6(2x-2)
=> (3x-7)/3 = 12x-12
=> 3x-7 = 36x -36
=> 3x-36x = 7-36
=> 33x = 29
=> x = 29/33.
Thus, Required answer will be 29/33.
Answered by
2
Solution:
Let a number thought by Manjula be x
According to the statement,
(x – 7 / 3) × 6 = 2x – 2
6x – 14 = 2x – 2
On further calculation, we get,
6x – 2x = - 2 + 14
4x = 12
x = 12 / 4
We get,
x = 3
Therefore, the required number is 3
Similar questions