Math, asked by gurnur1, 1 year ago

manjula thinks a number and subtracts7/3 from it .she multiplies the result by 6 the result obtained is 2 less than twice number the same number she thought of.what is the number

Answers

Answered by Monu631
50
Here is your answer.

Let the number she thought be x.

Now, As per the question,

(x-7/3) * 6 = 2x - 2

=> (x-7/3) = 6(2x-2)

=> (3x-7)/3 = 12x-12

=> 3x-7 = 36x -36

=> 3x-36x = 7-36

=> 33x = 29

=> x = 29/33.

Thus, Required answer will be 29/33.
Answered by Aadhya12345678910
2

Solution:

Let a number thought by Manjula be x

According to the statement,

(x – 7 / 3) × 6 = 2x – 2

6x – 14 = 2x – 2

On further calculation, we get,

6x – 2x = - 2 + 14

4x = 12

x = 12 / 4

We get,

x = 3

Therefore, the required number is 3

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