Math, asked by mansipankaj508, 30 days ago

MANOJ DEPOSITED A SUM OF ₹64000 IN A POST OFFICE FOR 3 YEARS , COMPOUNDED ANNUALLY AT 15/2% PER ANNUM . FIND THE COMPOUND INTREST HE GETS

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Answers

Answered by nikhil17870rrr
8

Step-by-step explanation:

Rs.79507

Step-by-step explanation:

Principal = Rs.64000

Time = 3 years

Rate of interest = 15/2 %

No. of compounds per year , n = 1

Amount =P(1+\frac{r}{n})^{nt}Amount=P(1+nr)nt

Amount =64000(1+\frac{15}{200})^{3}Amount=64000(1+20015)3

Amount =79507Amount=79507

Hence he will get Rs.79507 on maturity

hope it's helpful... dear.

Answered by Mbappe007
2

Required answer :

Principal = Rs.64000

Time = 3 years

Rate of interest = 15/2 %

No. of compounds per year , n = 1

\sf Amount = P ( \  1 + \dfrac{r}{t} \ )^{nt}

= \sf 64,000 \  ( \ 1 + \dfrac{15}{200} \  ) ^{3}

Therefore , the Amount = 79507

Hence he will get Rs.79507 on maturity

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