Question

Mansukh can do a piece of work in 10 hours. if he is joined by jayanti who is 50% more efficient, in what time will they together finish the work?

Answer 1

4 hours

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EXPLANATION

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Mansukh efficiency
= > 20 / 10 = 2



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jayanti is 50% more efficient than mansukh

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jayant efficiency
=> 150 / 100 * 2
=> 3 units / hour




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1 day work of mansukh and jayant

=> 2 + 3
=> 5 unit / hour


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Time taken to finish the work
=> 20 / 5
=> 4 hours





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HOPE THIS HELPS YOU


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Answer 2

Answer:

Together they can finish the work in 4 hours.

Step-by-step explanation:

It is given that Mansukh can do a piece of work in 10 hours.

The part of work done by Manusukh in 1 hour is $\frac{1}{10}$.

Let together they can finish the work in t hours.

The part of work done by them in 1 hour is $\frac{1}{t}$.

It is given that jayanti is 50% more efficient then Mansukh.

The part of work done by jayanti in 1 hour is

$\frac{1}{10}+\frac{1}{10}\times \frac{50}{100}= \frac{1}{10}+\frac{1}{20}=\frac{3}{20}$

Equate the part of work done by them in 1 hour.

$\frac{1}{10}+\frac{3}{20}=\frac{1}{t}$

$\frac{2+3}{20}=\frac{1}{t}$

$\frac{5}{20}=\frac{1}{t}$

$\frac{1}{4}=\frac{1}{t}$

$t=4$

Therefore together they can finish the work in 4 hours.