Question

many atoms are present in 9.0 g of aluminium 0.8 g of iron give at atomic mass of a is equal to 27 AMU f is equal to 56 amu
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Answer 1

Answer:

Explanation:

mole of aluminium = 9/27

= 0.3

atoms = 0.3 *6.022*10^23

= 1.8*10^23 atoms

mole of iron = 0.8/56

= 0.01

atoms = 0.01*6.022*10^23

= 6.022 *10^21 atoms