Math, asked by indu111134, 7 months ago

Manya, Gauray and sumeet flew paper
airpianes. Manya's plane flew 7 % feet,
Gaurav's plane flew 7.5 feet and
Sumeet's plane flew 7 5/6 feet. Whose plane
flew farthest ?​

Answers

Answered by RvChaudharY50
2

Given :-

  • Manya, Gauray and sumeet flew paper airpianes.
  • Manya's plane flew 7 feet.
  • Gaurav's plane flew 7.5 feet.
  • Sumeet's plane flew 7 5/6 feet.

To Find :-

  • Whose plane flew farthest ?

Solution :-

Given that,

→ Manya's plane flew = 7 feet.

→ Gaurav's plane flew = 7.5 = (15/2) feet.

→ Sumeet's plane flew = 7(5/6) = (47/6) feet.

So,

Taking LCM of denominators of given fractions we get,

→ LCM of 1, 2 and 6 = 6

Making denominator same of given fractions we get,

→ Manya's plane flew = 7 * (6/6) = (42/6) feet.

→ Gaurav's plane flew = 7.5 = (15/2) * (3/3) = (45/6) feet.

→ Sumeet's plane flew = 7(5/6) = (47/6) feet.

Now, comparing all fractions we get,

→ 42 < 45 < 47

Or,

→ (42/6) < (45/6) < (47/6)

Or,

Manya's plane < Gaurav's plane < Sumeet's plane.

Therefore, Sumeet's plane Flew farthest.

Learn more :-

Which is the largest ratio 5/36, 2:9, 3 to 18, 1:3

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