Question

Mar
6. ID a + b + c = 9 and ab + bc + ca = 26, then find a + b + c?​

Answer 1

Answer:

Given, a + b + c = 9

and ab + bc + ca = 26

To find, $a^{2} + b^{2} + c^{2}$

Step-by-step explanation:

=> $( a + b + c)^{2} = a^{2} + b^{2} + c^{2} + 2(ab + bc + ac)\\ a^{2} + b^{2} + c^{2} = ( a + b + c)^{2} - 2(ab + bc + ac)$

On placing the values we get,

$a^{2} + b^{2} + c^{2} =$

$9^{2} + 2(26)\\= 81 + 52\\= 133$

I hope it helps you! # brainliest