Question

Maria is 22 years younger than her mother after 6 year sum of their ages will be 50 years find their age​

Answer 1

Answer:

mother's age is 30year

Maria's age is 8 year

Step-by-step explanation:

let age of mother be x

let age of Maria be x-22

after 6

mother's age be x+6

Maria's age be x-22+6= x-16

sum of their ages after 6 years is 50

so, x+6 + x-16 = 50

2x-10= 50

2x =60

x=30

Answer 2

To find:-

• Age of Maria
• Age of Maria's Mother.

Assumption:-

• Let mother's age be x
• Age of Maria = x-22

Solution:-

After 6 years,

Age of Mother = x+6

Age of Maria = x-22+6

Given that the sum of their ages will be 50 years.

ATQ

= (x+6)+(x-22+6) = 50

=> x+6+x-22+6 = 50

=> 2x + 12 -22 = 50

=> 2x -10 = 50

=> 2x = 50+10

=> 2x = 60

=> x = 60/2

=> x = 30

Therefore,

Age of Maria = x - 22 = 30 - 22 = 8 years

Age of Maria's mother = x = 30 years.