Question

Maria walked 3km west then 4km south. Draw a diagram to represent this and find out how far she is from her starting point.​

Answer 1

Answer:

5 km

Step-by-step explanation:

As per the information provided in the question, We have :

• Maria walked 3km west then 4km south.

• Let's consider ABC is the triangle.

Where,

• AB = Base = 3 km
• BC = Perpendicular = 4 km
• Hypotenuse = CA

We are asked to calculate the how far she is from her starting point, As we know, Displacement is the distance between the initial to final position of the object.

Thus, We have to find displacement.

In order to find displacement of Maria, We will use Pythagoras theorem,

It is given by —

$\longmapsto \rm (CA)^2 = (AB)^2 + (BC)^2$

Putting the given values to find the unknown values,

$\longmapsto \rm (CA)^2 = (3)^2 + (4)^2$

$\longmapsto \rm (CA)^2 = 9 + 16$

$\longmapsto \rm (CA)^2 = 25$

$\longmapsto \rm CA = \sqrt{25}$

$\longmapsto \rm CA = 5 \: km$

∴ Displacement is 5 km. Thus, Maria is 5 km far from her starting point.

[ Refer to the diagram for better understanding ]

Answer 2

Question :

Maria walked 3km west then 4km south. Draw a diagram to represent this and find out how far she is from her starting point.

Solution :

According to the diagram

4 km is the Height

3 km is the Base

So the Hypotenuse is not given hence we need to find it out

In the case

We need to use Pythagoras Theorem

In ∆ABC, ∠B = 90°

(AC)² = (AB)² + (BC)²

(AC)² = (4)² + (3)²

(AC)² = 16 + 9

(AC)² = 25

AC = √25

AC = 5

∴ She is 5 km far from her starting point

Diagram is in the attachment