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Q2. Mary is ‘x’ years old. Write an algebraic expression for each of the following. [4]
a)Three times Mary’s age next year.
b) Five times Mary’s age 6 years ago.
c) Mary’s aunt’s age if she is 27 years older than her.
d)Mary’s niece’s age when she is 17 years younger than her.
Answers
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Answer :-
a)
Mary's age next year = x + 1
Three times Mary's age next year = 3(x + 1)
Algebraic expression = 3x + 3
b)
Mary's age 6 years ago = x - 6
Five times Mary's age 6 years ago = 5(x - 6)
Algebraic expression = 5x - 30
c)
Mary's aunt is 27 years older than her. So,
Mary's aunt age = Mary's age + 27
We are given that, Mary's age is x
Hence, Mary's aunt age = x + 27
Algebraic expression = x + 27
d)
Mary's neice age when she is younger 17 years younger than her = Mary's age - 17
= x - 17
Algebraic expression = x - 17
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