Question

Marks Obtained by X in physics is 160 which is 40% of total marks obtained by him. and marks obtained by z in chemistry is3/4th of marks obtained by X in physics. Ratio of total marks obtained by X to Z is 4:3. Marks obtained by Y in Maths is equal to marks obtained by Z in chemistry. And total marks obtained by Y in physics and chemistry together is half of total marks obtained by X.
If marks obtained by X in Maths is 50% more than marks obtained by him in chemistry, Then find the difference of marks obtained by X in Maths and marks obtained by Y in maths?

Answer 1

Answer:

Question: The total marks obtained by a student in Physics, Chemistry and Mathematics together are 120 more than the marks obtained by him in Chemistry. How should I calculate the average marks obtained by him in Physics and Mathematics together?

A60

B120

C40

DCannot be determined

ENone of these

Posted by: Anand S. on 21.09.2017

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Answer 2

Answer:

The difference of marks obtained by X in Maths and marks obtained by Y in Maths = 24

Step-by-step explanation:

Given,

1. Marks obtained by X in physics = 160 = 40% of total marks of X2.
2. Marks obtained by Z in Chemistry = $\frac{3}{4}$th of marks obtained by X in physics
3. Ratio of total marks obtained by X to Z is 4:3
4. Marks obtained by Y in Maths = Marks obtained by Z in chemistry
5. Total marks obtained by Y in physics and chemistry together is half of total marks obtained by X.
6. The marks obtained by X in Maths is 50% more than marks obtained by him in chemistry,

To find,

Marks of X in Maths - Marks of Y in Maths

Solution:

To find the marks of X in Maths

From (1)

Marks obtained by X in Physics = 160

Total Marks obtained by X ×40% = 160

Total marks obtained by X = 160×$\frac{100}{40}$ = 400

From(6), The marks obtained by X in Maths is 50% more than marks obtained by him in chemistry,

If x is the marks obtained by X in Chemistry, then marks in Maths = x+50%x

x+$\frac{1}{2}$x = $\frac{3}{2}$x

Since the total marks of X is 400, we have

x+ $\frac{3}{2}$x+160 = 400

$\frac{5}{2}$x = 240

x = 96

Marks of X in Chemistry = 96

Marks of X in Maths =  $\frac{3}{2}$x =  $\frac{3}{2}$×96 = 144

To find the marks of Y in Maths

From(2) Marks obtained by Z in Chemistry = $\frac{3}{4}$th of marks obtained by X in physics

Since Marks obtained by X in Physics = 160,  

Marks obtained by Z in Chemistry =  $\frac{3}{4}$ ×160 = 120

From (4) ,Marks obtained by Y in Maths = Marks obtained by Z in chemistry

Marks obtained by Y in Maths = 120

Marks of X in Maths - Marks of Y in Maths = 144 - 120

= 24

∴ Marks of X in Maths - Marks of Y in Maths = 24

Answer:

The difference of marks obtained by X in Maths and marks obtained by Y in Maths = 24

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