mary invests £12000 in a savings account.
the amount pays 1.5% compound interest each year
work out the value of her income in 2 years
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1
Answer:
Step-by-step explanation:
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Answer:
The value of Mary's investment after two years = £12362.7
Step-by-step explanation:
P = Principal / initial amount
R = rate of interest per cent per year
T = number of years
A = final amount at the end of T years
Then:
A = P*(1 + R/100)^2
In our example:
P = £12000
R = 1.5 per cent per year
T = 2 years
Thus:
A = 12000*(1 + 1.5/100)^2
= 12000*(1 + 0.015)^2
= 12000*(1.015)^2
= 12000*(1.030225)
= 12362.7
Value of investment after two years = £12362.7
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