Question

mary is 3times older than nandhini after 10 yrs the sum of their ages will be 80 find their present age.answer with algebraical method

Answer 1

Answer:

Nandhini = 15 years

Mary = 45 years

Step-by-step explanation:

Let Nandhini be x yrs old

Then, Mary would be 3x yrs old

After ten years the ages will be as

Nandhini = (x + 10) yrs

Mary = (3x + 10) yrs

ACQ.

(x + 10) +  (3x + 10) = 80

⇒ 4x 20 = 80

⇒ 4x = 80 - 20

⇒ 4x = 60

⇒ x = 60/4

⇒ x = 15

So, the present ages are :

Nandhini = 15 yrs

Mary = 45 yrs ...............( 3x = 3 X 15 = 45)