Question

Mary is twice older than her sister.in 5 years time,she will be 2 years older than her sister. find how old are they both now...​

Answer 1

Answer:

let present age of Mary's sister be x

so, Mary present age is 2x

After 5 years

Mary's sister age = x+5 years

Mary's age = 2x+5

A.T.Q

2x+5 = (x+5) + 2

2x+5 = x+5+2

2x+5 = x+7

2x-x = 7-5

x = 2

therefore, Mary's sister present age is 2 years.

Mary's present age is 4 years.

Step-by-step explanation:

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Answer 2

☆Your answer☆

let the present age of Mary's sister be x

Mary's present age is 2x

after 5 years

Mary's sister age = x + 5 years

Mary's age = 2x + 5 years

A.T.Q

2x + 5 = ( x + 5 ) + 2

2x + 5 = x + 5 + 2

$\: \: \: \: \: \: \: = x + 7$

2 x - x = 7 -5

x = 2

so,

• Mary's sister present age is 2 years
• Mary's age is 4 years

i hope this will help you...