Mary is twice older than her sister in 5 years time she will be 2 years older than her sister find to old they both now
bethelchazie:
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Answered by
22
Let Mary be x and her sister y. Mary is two times her sister, so:
x = 2y We'll use this value for x next.
In 5 years:
x+5 = (y+5)+2 Substitute for x:
2y+5 = (y+5)+2
2y+3 = y+5
y = 2
------------
Check:
the sister is 2 and Mary is 2*2=4
In 5 years:
2+5=7
4+5=9
and 9-7 = 2, so in 5 years Mary will be 2 years older than sister. CORRECT
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x = 2y We'll use this value for x next.
In 5 years:
x+5 = (y+5)+2 Substitute for x:
2y+5 = (y+5)+2
2y+3 = y+5
y = 2
------------
Check:
the sister is 2 and Mary is 2*2=4
In 5 years:
2+5=7
4+5=9
and 9-7 = 2, so in 5 years Mary will be 2 years older than sister. CORRECT
Please mark as brainliest
Answered by
67
Define x:
Let her sister be x years old
Mary = 2x
Express their age in 5 years time:
Sister = x + 5
Mary = 2x + 5
Form equation:
Mary will be 2 years older than her sister
⇒ 2x + 5 = (x + 5) + 2
Solve x:
2x + 5 = (x + 5) + 2
2x + 5 = x + 5 + 2
2x + 5 = x + 7
x = 2
Find their current age:
Sister = x = 2
Mary = 2x = 4
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