MASS IN GRAMS OF 5.136 MOLES OF AG2CO3
Answers
Answered by
5
Answer:
m = 1415.48 grams
Explanation:
molar mass of Ag2Co3 = 107.8× 2+ 12 + 16×3 = 275.6 u
number of moles = given mass/ molar mass
5.136 = m/ 275 6
m = 1415.48grams
Answered by
1
Answer:
꧁P꧁R꧁I꧁N꧁C꧁E꧂
Explanation:
___➡️ M = 1415 . 48Grams ⬅️____
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