Question

Mass of a substance measured by the student is 1.56, 1.60, 1.62, 1.58 gm. The average absolute error in the measurement is​

Answer 1

given masses: 1.56g,xˉΔxiΔx1Δx21.60g,1.62g,1.52g=41.56+1.60+1.62+1.52=1.575 g=∣xˉ−xi∣=∣1.56−1.575∣=0.015 g=0.025 g

△x3=0.045 gΔx4=0.055 g mean error =40.015+0.025+0.045+0.055=40.14=0.035

Answer 2

Answer:

The average absolute error is 0.02

Explanation:

here mean = (1.56 +1.60+1.62+1.58)/4 =1.59

we know, error = ∑ | xi -x! |/n

error =(| 1.59 - 1.56|+|1.59-1.60|+|1.59-1.62|+|1.59-1.58|)/4

error =(0.03+0.01+0.03+0.01)/4

error =0.08/4

error = 0.02