Question

Mass of acetic acid present in 800ml of binormal soln is

Answer 1

10%( vw ) acetic acid means 10g acetic acid in 100ml water.

Thus, 100g of Acetic acid would be present in 1000ml of water.

60g=1mole of acetic caid.

∴100g= 60/100

=1.67molesofCh3

CO 2 H

Thus, 1.67moles present in 1L of water.

i.e. the solution is 1.67M

In case of CH 3CO 2

H,1Nsolution=1Msolution

Thus, normality of 10% acetic acid=1.67