mass of bullet is 0.03kg fire 200 in a sec fire with 50 m/s and reflect back with 30m/s
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Mass of the body = 0.03 kg .
Final momentum = 200 × 0.03 kg × (-30 m/s)
⇒ - 2 × 3 × 30 kg m/s
⇒ - 6 × 30 kg m/s
⇒ - 180 kg m/s
Initial momentum = 200 × 0.03 kg × 50 m/s
⇒ 2 × 3 × 50 kg m/s
⇒ 6 × 50 kg m/s
⇒ 300 kg m/s
Change in momentum = 300 kg m/s - ( -180 kg m/s )
⇒ 480 kg m/s .
Average force acting = change in momentum / time taken
⇒ 480 kg m/s / 1 s
⇒ 480 kg m/s²
⇒ 480 N
Answered by
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Answer:
[Mass of the bullet = 0.03 kg .]
Final momentum = 200 × 0.03 kg × (-30 m/s)
⇒ - 2 × 3 × 30 kg m/s
⇒ - 6 × 30 kg m/s
⇒ - 180 kg m/s
Initial momentum = 200 × 0.03 kg × 50 m/s
⇒ 2 × 3 × 50 kg m/s
⇒ 6 × 50 kg m/s
⇒ 300 kg m/s
Change in momentum = 300 kg m/s - ( -180 kg m/s )
⇒ 480 kg m/s .
Average force acting = change in momentum / time taken
⇒ 480 kg m/s / 1 s
⇒ 480 kg m/s²
⇒ 480 N
Explanation:
Momentum = mass × velocity .
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