Question

mass of CaO formed during the release of 2.2 g CO2 from calcium carbonate​

Answer 1

Answer:

2.2 g

Explanation:

CaCO3 ---> CaO +CO2

n Proptional to volume

1 ----> 1

2.2 ---> x

x= 2 .2g

Answer 2

Chemical reaction involved is:

CaCO

3

→CaO+CO

2

Molar mass of CaCO

3

=40+12+16×3=100 g

According to the balanced reaction 100 g of CaCO

3

produces 1 mol of CO

2

i.e. 22.4 L at STP.

∴50 g CaCO

3

will produce

100

22.4

×50=11.2 L CO

2

at STP.

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