Question

number consists of two digits whose sum is 9 if 27 is subtracted from the number it's digits are reversed find the number ​​

Answer 1

Answer :

The number = 63

Explanation :

According to the question :

↪Let the unit place digit be ' x '

Sum of digit = 9 { given }

↪Tens place digit of the number = 9 - x

↪The number = 10 ( 9 - x ) + x ...... [ 1 st equation ]

↪Reversed = 10x + ( 9 - x ) ...... [ 2 nd Equation ]

27 subtracted = [ 10 ( 9 - x ) + x ] - 27

Equation :

⟹ 10 ( 9 - x ) + x - 27 = 10x + ( 9 - x )

⟹ 90 - 10x + x - 27 = 10x + 9 - x

⟹ ( x - 10x ) + ( 90 - 27 ) = ( 10x - x ) + 9

⟹ -9x + 63 = 9x + 9

⟹ -9x - 9x = 9 - 63

⟹ -18x = -54

⟹ x = $\frac{-54}{-18}$

⟹ x = $\frac{\cancel{-54}}{\cancel{-18}}$

⟹ x = 3

To find :

➳ Unit place of the number = x = 3

➳ Tens place of the number = 9 - x

= 9 - 3 = 6

➳ So, The number is = 63

So, It's Done !!

Answer 2

Answer:

36 or 63 can be the number

Step-by-step explanation:

Assuming

x as tens digit

y as ones digit

Their sum :

x + y = 9 ..... (i)

Number formed :

10x + y

Interchanging the digits :

10y + x

According to the question :

➡ (10x + y) - (10y + x) = 27

➡ 9x - 9y = 27

➡ 9(x - y) = 27

➡ x - y = 27/9

➡ x - y = 3 ..... (ii)

Subtracting both the equation :

$\bf \: x + y = 9 \\ { \underline{ \bf{x - y = 3}}} \\ \implies \bf \: 2x = 6 \\ \implies \bf \: x = 3$

Substituting the value of x in equation (i) :

➡ x + y = 9

➡ 3 + y = 9

➡ y = 6

Hence

The number can be 10x + y

or, 10(3) + 6

or, 36 either 63