Chemistry, asked by raneethareddy31, 7 months ago

Mass of iron = Initial mass – Final mass = 15.5 – 8.5 = 7.0g Mass of copper (II) sulfate = 21.0g Mass of copper = 8.60g According to law of conservation of mass, Mass of iron + Mass of copper (II) sulfate = Mass of copper + Mass of iron (II) sulfate 7.0g + 21.0g = 8.60g + Mass of iron (II) sulfate So, Mass of iron (II) sulfate = 19.40g

Answers

Answered by maheevijay0616
0

Explanation:

Initial mass – Final mass= 15.5 – 8.5 = 7.0gMass of copper (II) sulfate = 21.0gMass of copper = 8.60gAccording to law of conservation of mass,Mass of iron + Mass of copper (II) sulfate = Mass of copper + Mass ofiron (II) sulfate7.0g + 21.0g = 8.60g + Mass ofiron (II) sulfateSo,Mass of iron (II) sulfate = 19.40g8

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