Mass of one atom of the element A is 3.9854×10^-23 g. How many atoms are contained in 1g of element A is?
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In any element or substance, the number of atoms contained in 1 mole is 6.023 × 10²³ atoms. This is Avogadro's number and is constant in 1 mole of every substance.
mass of 1 atom = mass of a mole of atoms / 6.022 x 10²³
That is molar mass = Avogadro's number × mass of 1 atom
molar mass for A = 6.022 x 10²³ × 3.9854×10⁻²³
= 24
Molar mass of element A is 25g/mol
Find number of atoms in 1 gram of element:
If molar mass is 24 g/mol means 1 mole has 24g.
If 24g = 1 mole = 6.022 x 10²³ atoms
Then 1g = 6.022 x 10²³ × 1g/24g
= 2.5091667 ×10²² atoms
Therefore 1g of element A has 2.5091667 ×10²² atoms
mass of 1 atom = mass of a mole of atoms / 6.022 x 10²³
That is molar mass = Avogadro's number × mass of 1 atom
molar mass for A = 6.022 x 10²³ × 3.9854×10⁻²³
= 24
Molar mass of element A is 25g/mol
Find number of atoms in 1 gram of element:
If molar mass is 24 g/mol means 1 mole has 24g.
If 24g = 1 mole = 6.022 x 10²³ atoms
Then 1g = 6.022 x 10²³ × 1g/24g
= 2.5091667 ×10²² atoms
Therefore 1g of element A has 2.5091667 ×10²² atoms
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By cross multiplication
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