Question

mass of oxalic acid require to prepare 100ml of semimolar solution​

Answer 1

Answer:

4.5 is the answer .

Explanation:

mass of solute = M × v ( ml ) × gmwt / 1000

=0.5 ×100 ×90/ 1000

= 4.5

hope its help u.............TC❤

Answer 2

Answer:

108g

Explanation:

Formula of oxalic acid = C2H2O4

Molar mass of oxalic acid = 12 x2 + 1 x 2 + 16 x 4 = 90 g/mol

Now semimolar solution means molarity = 12 M

Let the no. Of moles of oxalic acid required to form 100 ml of 12M solution = a moles

Then (a x 1000)/100 = 12 ____{(no. of moles ) x 1000}/vl. of solution = M

..... 10a = 12

......a = 1.2 moles.

Hence mass of oxalic acid = 1.2 x 90 = 108 g.