Mass of oxygen required for the complete combustion of 40 g of methane is
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mass of Methane = 16 g
mass of 2 molecules of oxygen = 64 g
The equation shows that 16 g of methane requires 64 g of Oxygen
1.61.6g of methane requires 64×1.6/16 = 6.4 g of oxygen
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Answer:
6.4 g of oxygen..
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