Question

Mass of the Jupiter is 2*10²⁷ kg and its radius is 7.14 * 10⁷ m. Calculate gravitaional acceleration on its surface.

GSEB - Class 9 Chapter - 3.Gravitation Page 44

Answer 1

Answer:

The gravitational acceleration on the surface of the Jupitor is 26.17 m/s²

Explanation:

The formula for the gravitational acceleration g is

$\boxed{g=\frac{GM}{R^2}}$

Where,

G is the gravitaional constant = 6.67 x 10⁻¹¹ Nm²/kg⁻²

M is the mass of the planet

R is the radius of the planet

In this question, given is

M = 2 × 10²⁷ kg

R = 7.14 × 10⁷ m

Therefore,

$g=\frac{6.67\times 10^{-11}\times 2\times 10^{27}}{(7.14\times 10^7)^2}$

$\implies g=\frac{6.67\times 2\times 10^{16}}{50.98\times 10^{14}}$

$\implies g=0.2617\times 10^2$

$\implies g=26.17$ m/s²

Answer 2

$\huge \rm g = 26.17m {s}^{2}$