Question

Mass of the sun is 2×10^30(10raised power 30)kg and that of the earth is 6 x 10^24.if the average distance between the sun and the earth is 1.5×10^11(10raise to power 11)m, calculate the force exerted by the sun on the earth and also by the earth on the sun

Answer 1

Explanation:

If the mass of the sun is 2 into 10 raise to power 30 kg the distance of the earth from the sun is 1.5 into 10 raise to power 11 metre and period of revolution of the earth around the sun is 1 year calculate the value of the gravitational constant?

Scan & pay on Amazon.

M=mass of sun m=mass of earth F(gravitational) =F(centripetal)

T = 1 year = 365x24x3600 = 31,556,926 ~3.16 x 10 ^7 s

F =GMm/r^2 G=Fr^2/Mm F(centr.) = mv^2/r so G =(mv^2/r)(r^2/Mm)

G = (2pi.r/T)^2(r/M) =4 pi^2 r^3/T^2M now plug in

r =1.5x10^11 meters M = 2x10^30 kg T = 3.16 x 10^7 s and you should get close to

G = 6.67 x 10^(-11) [Nm^2/kg^2]

Note the m’s cancel and v =2pi.r/T

Answer 2

Given:-

• Mass of the Sun (M) = 2×10^30

• Mass of Earth (m') = 6×10^24

• Gravitational constant (G) = 6.7×10^-11
• Distance between them (d) = 1.5×10^11

To Find:-

• The force exerted by the sun on the earth and also by the earth on the sun.

Solution:-

By using this formula

⟹ F = G×M×m/d²

Putting all the values which is given above

⟹ F = 6.7×10^-11×2 ×10^30 ×6×10^24/(1.5×10^11)²

After solving we get the final result

⟹ F = 3.57× 10^22 N