Chemistry, asked by jimitpatel085, 9 months ago

mass percentage proportion of carbon in ethanol ch=1,c=12,o=16​

Answers

Answered by priyankmrunal
0

Answer:

Ethanol=C2H5OH

Total mass of ethanol=(12×2)+(1×5) +(16×1) +(1×1)

=24+5+16+1

=46

Total mass of Carbon molecules in ethanol=12×2=24

Mass percentage proportion of carbon in ethanol=(24/46) ×100=52.17%

Hope it helps you.

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