mass percentage proportion of carbon in ethanol ch=1,c=12,o=16
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Answer:
Ethanol=C2H5OH
Total mass of ethanol=(12×2)+(1×5) +(16×1) +(1×1)
=24+5+16+1
=46
Total mass of Carbon molecules in ethanol=12×2=24
Mass percentage proportion of carbon in ethanol=(24/46) ×100=52.17%
Hope it helps you.
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