Question

Please Answer Soon! Thank you! In any isosceles triangle ABC with AB=AC, the altitude AD bisects the base BC so that BD=DC. Determine the area of triangle ABC.

Answer 1

Answer:

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Answer 2

Answer:

BD=DC

BD+DC=14

BD+BD=14

2(BD)=14

BD=7

In triangle ABD

AB²=BD²+AD²

AD=

$\sqrt{ {25}^{2} - {7 \\ }^{2} } \\ = \sqrt{625 - 49 } \\ = \sqrt{576} \\ = 24cm$

Area of triangle ABC=

$\frac{1}{2} \times b \times h \\ = \frac{1}{2 } \times 14 \times 24 \\ = 14 \times 12 \\ = 168 {cm}^{2}$

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