Question

MAT (15)
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9. Around a square pool, there is a footpath of
width 3cm.
If the area of the footpath is times that
5/4
of the
pool, then the area of the pool is​

Answer 1

Answer:

let the side of pool be x

so side of footpath square will be x+2*3

=x+6

area of pool = x^2

area of footpath = (x+6)^2-x^2

the area of the footpath is times that

5/4 of the pool

5/4 x^2 = (x+6)^2-x^2

5x^2 = 144 +48 x

5x^2 -144 -48 x=0

gives root x=12 or -12/5

neglect the negative value

area of pool will be 12*12= 144 sq cm