Question

Match the following


Column – I Column – II

(A) SF4 (p) Lone pair is present in axial position

(B) PCl3F2 (q) Lone pair is present in equatorial position

(C) XeF4 (r) F atoms are present in axial position

(D) XeF-5 (s)  (dipole moment) = 0

(t) Non – planar

Answer 1

Answer:

sorry i dont no mark the qu

Answer 2

Match the following

Explanation:

• $SF_{4}$ has square planar hybridization which has 1 lone pair. lone pair present on equatorial position.

• $PCl_{3}F_{2}$ has hybridization trigonal-bipyramidal where F (fluorine) more electronegative than chlorine so F present on axial position due to lower repulsion on this position. This molecule possess zero dipole moment. It match with both option r and t

• $XeF_{4}$ has octahedral hybridization where 2 lone pair are present on axial position. It match with option p

• $XeF_{5}$ has hybridization square pyramidal.