Question

math part 1 9th standard ​

Answer 1

$\frac{x}{7 } = \frac{y}{3} = \frac{3x + 5y}{36} = \frac{7x - 9y}{22}$

$\frac{a}{3} = \frac{b}{4} = \frac{c}{7} = \frac{a - 2b + 3c}{16} = \frac{2a - 2b + 2c}{6 - 8 + 14}$