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Qno.2
First the root of polynomial=2
X=2
X-2=0
One factor is x-2
By dividing polynomial by x-2
We get=2x²+x-15
It means=(x-2)(2x²+x-15)
By factorising 2x²+x-15
We get=2x²+6x-5x-15
Further processing
2x(x+3)-5(x+3)
=(x+3)(2x-5)
Thus factorising of 2x³-3x²-17x+30
=(x-2)(x+3)(2x-5)
Qno. 4
X³+x²-4x-4
x²(x+1)-4(x+1)
(x+1)(x²-4)
Thus we know two factors
First the root of polynomial=2
X=2
X-2=0
One factor is x-2
By dividing polynomial by x-2
We get=2x²+x-15
It means=(x-2)(2x²+x-15)
By factorising 2x²+x-15
We get=2x²+6x-5x-15
Further processing
2x(x+3)-5(x+3)
=(x+3)(2x-5)
Thus factorising of 2x³-3x²-17x+30
=(x-2)(x+3)(2x-5)
Qno. 4
X³+x²-4x-4
x²(x+1)-4(x+1)
(x+1)(x²-4)
Thus we know two factors
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