Question

mathematics class 8 question
5. the measure of two adjacent angles of a parallelogram are in the ratio 3:2 find the measure of each of the angles of the parallelogram​

Answer 1

☞Solution:-

Let two adjacent angles A and B of ∥gm

ABCD be 3x and 2x respectively.

ABCD be 3x and 2x respectively.Since the adjacent angles of a parallelogram are supplementary.

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∠A+∠B=180

∠A+∠B=180 ⇒3x+2x=180

∠A+∠B=180 ⇒3x+2x=180 ⇒5x=180

$x = \frac{180}{5}$

x = 36 degree

∴ ∠3×36 degree

=108 degree

and, ∠B=2×36

and, ∠B=2×36 =72

and, ∠B=2×36 =72

and, ∠B=2×36 =72 Since the opposite angles are equal in a parallelogram, therefore, ∠C=∠A=108 degree and ∠D=∠B=72 degree.

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Hence, ∠A=108 degree.

∠B=72 degree

∠C=108 degree

and ∠D=72 degree.

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HOPES, IT'S HELPFUL.

Answer 2

Answer:

let the angles be 3x,3x,2x,2x..[since opposite angles of  a parallelogram are equal]

3x+3x+2x+2x=360   [sum of all angles of a quadrilateral is 360degrees]  

10x=360

x=360/10

x=36

now,

3x= 36*3 = 108

2x= 36*2= 72

therefore the measures of all the angles are 108,72,108,72.

hope this is helpful...i wrote this answer for the pov of 3marks