Question

MATHEMATICS-X
52. In Fig. 8.80, PA and PB are tangents to the circle from an external point P. CD is
another tangent touching the circle at Q. If PA = 12 cm, QC - QD =3 cm, then find
PC + PD
ICBSE 2017)
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Answer 1

Step-by-step explanation:

1. You can also see that C is an external point and CQ and CA are tangents.
2. We know, tangents from the same point has same measure (length).
3. We know, CQ= 3 cm, so CA is also equals to 3 cm.
4. Length of PA is given, so PC= PA- CA= 9 cm.
5. As PA and PB are tangents from the same point(P) PB= PA= 9 cm.
6. So, PA+ PB= 18 cm. (ANSWER)

Mission Accomplished!!!!! Please mark me brainliest.

Answer 2

Answer:

since it's given that PA =12 cm

we know that length of tangents drawn from an external points to a circle are equal

so

PA =PB =12 cm

and since CD is also an another tangent so

AC=QC and BD=QD

it's given that QC=QD =3

so

AC= QC=3cm

from fig

PA =AC+PC

12=3+PC

12-3=PC

9 = PC

same for PD

PC +PD

9+9

18