मध्याह्न का वर्ण विच्छेद क्या होगा बताइए
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Answered by
0
Answer:
−1−secAtanA=2⋅cosecA
L.H.S
1+secAtanA−1−secAtanA
=1−sec2AtanA(1−secA)−tanA(1+secA)
=−tan2AtanA(1−secA−1−secA)
=−tanA−2secA
=sinA/cosA2⋅1/cosA
=sinA2
=2⋅cosecA
=R.H.S
∴ L.H.S=R.H.S.
Answered by
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Answer:
Refer to the picture for your answer....
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