Math, asked by rk8359041, 9 months ago

\mathrm{a}_{\mathrm{n}}=\int_{0}^{\frac{\pi}{2}} \frac{1-\cos 2 \mathrm{nx}}{1-\cos \mathrm{x}} \mathrm{dx},a
n
​ =∫
0
2
π


1−cosx
1−cos2nx
​ dx, then \mathrm{f}(\mathrm{x})=\left|\begin{array}{lll}\mathrm{a}_{1} & \mathrm{a}_{2} & \mathrm{a}_{3} \\ \mathrm{a}_{4} & \mathrm{a}_{5} & \mathrm{a}_{6} \\ \mathrm{a}_{7} & \mathrm{a}_{8} & \mathrm{a}_{9}\end{array}\right| \forall \mathrm{x} \in \mathrm{R} ;f(x)=







a
1

a
4

a
7


a
2

a
5

a
8


a
3

a
6

a
9








​ ∀x∈R; then \mathrm{f}(1)=f(1)=

Answers

Answered by xxiTzSiLeNtKiLlErxx
3

 &lt;marquee&gt; <strong><em><u>u dont know coadings xd!</u></em></strong></p><p>

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