Maths-10th-Trigonometry-
If tanA=cotB and A and B are acute then prove that A+B=90deggers.
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Answered by
3
We know that tanA= CotB
tanA= tan (90-B)
Because we know the formula cot(90-A)=tanA.
So by cancelling tan on both the sides,
A=90-B
Taking all variables to one side
A+B= 90 degrees.
HOPE IT HELPS YOU... ☺☺☺☺
tanA= tan (90-B)
Because we know the formula cot(90-A)=tanA.
So by cancelling tan on both the sides,
A=90-B
Taking all variables to one side
A+B= 90 degrees.
HOPE IT HELPS YOU... ☺☺☺☺
Akhilkumar01:
Thank u very muct
Answered by
3
Hello !
Given,
tan A = cot B
also,
tan A = tan ( 90 - B)
i.e.,
A = 90 - B
A + B = 90
Proved.
Given,
tan A = cot B
also,
tan A = tan ( 90 - B)
i.e.,
A = 90 - B
A + B = 90
Proved.
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