Question

maths 12th sum all bits

Answer 1

4sinϴ=3cosϴ

4/3=sinϴ/cosϴ

4/3=tanϴ

so, opposite side=4units

adjacent side=3 units

by pythagorous theorem,

hyp=5units

1)sinϴ=opp/hyp=4/5

2)cosϴ=adj/hyp=3/5

3)cot^2ϴ-cosec^2ϴ=(3/4)^2-(5/4)^2=9/16-25/16=-16/16=-1

4)4cos^2ϴ-3sin^2ϴ+2=4(3/5)^2-3(4/5)^2+2=4(9/25)-3(16/25)+2

=36/25-48/25+2=-12/25+2=-12+50/25=38/25